Quiz:Piecewise definition of function: Difference between revisions
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- <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 2x + 1, & -1/2 < x < 0 \\ -2x - 1, & -1 \le x \le -1/2 \\ -1, & x \le -1 \\\end{array}\right.</math> | - <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 2x + 1, & -1/2 < x < 0 \\ -2x - 1, & -1 \le x \le -1/2 \\ -1, & x \le -1 \\\end{array}\right.</math> | ||
{Suppose <math>a < b</math> are real numbers. For an real number <math>x</math>, define <math>f(x)</math> as the minimum of the distances from <math>x</math> to <math>a</math> and <math>b</math>. In other words, <math>f(x) := \min \{ |x - a|, |x - b| \}</math>. Which of the following is the correct piecewise linear definition of <math>f</math>? | {Suppose <math>a < b</math> are real numbers. For an real number <math>x</math>, define <math>f(x)</math> as the minimum of the distances from <math>x</math> to <math>a</math> and <math>b</math>. In other words, <math>\! f(x) := \min \{ |x - a|, |x - b| \}</math>. Which of the following is the correct piecewise linear definition of <math>f</math>? | ||
|type="()"} | |type="()"} | ||
- <math>\left \lbrace\begin{array}{rl} a - x, & x \le a \\ x - (a + b)/2, & a <x < b \\ x - b, & x \ge b \\\end{array}\right.</math> | - <math>\left \lbrace\begin{array}{rl} a - x, & x \le a \\ x - (a + b)/2, & a <x < b \\ x - b, & x \ge b \\\end{array}\right.</math> | ||
Revision as of 22:14, 19 October 2011
This quiz is related to piecewise definition of function.
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