Quiz:Piecewise definition of function: Difference between revisions
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- <math>\left \lbrace\begin{array}{rl} 1, & x \ge -1 \\ -1, & x < -1 \\\end{array}\right.</math> | - <math>\left \lbrace\begin{array}{rl} 1, & x \ge -1 \\ -1, & x < -1 \\\end{array}\right.</math> | ||
- <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 0, & -1 < x < 0 \\ | - <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 0, & -1 < x < 0 \\ -1, & x \le -1 \\\end{array}\right.</math> | ||
+ <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 2x + 1, & x < 0 \\ -1, & x \le -1 \\\end{array}\right.</math> | + <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 2x + 1, & -1 < x < 0 \\ -1, & x \le -1 \\\end{array}\right.</math> | ||
- <math>\left \lbrace\begin{array}{rl} 2x + 1 < x \ge -1/2 \\, -2x - 1, & x < -1/2 \\\end{array}\right.</math> | - <math>\left \lbrace\begin{array}{rl} 2x + 1 < x \ge -1/2 \\, -2x - 1, & x < -1/2 \\\end{array}\right.</math> | ||
- <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 0, & 2x + 1, & -1/2 < x < 0 \\ -2x - 1, & -1 \le x \le -1/2 \\ -1, & x \le -1 \\\end{array}\right.</math> | - <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 0, & 2x + 1, & -1/2 < x < 0 \\ -2x - 1, & -1 \le x \le -1/2 \\ -1, & x \le -1 \\\end{array}\right.</math> | ||
Revision as of 21:54, 19 October 2011
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