Quiz:Piecewise definition of function: Difference between revisions
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This quiz is related to [[piecewise definition of function]]. | This quiz is related to [[piecewise definition of function]]. | ||
==Pointwise combination== | ==Converting to and from piecewise definitions== | ||
<quiz display=simple> | |||
{Which of the following is the correct piecewise linear definition for <math>|x + 1| - |x|</math>? | |||
|type="()"} | |||
- <math>\left \lbrace\begin{array}{rl} 1, & x \ge -1 \\ -1, & x < -1 \\\end{array}\right.</math> | |||
- <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 0, & -1 < x < 0 \\ -1, & x \le -1 \\\end{array}\right.</math> | |||
+ <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 2x + 1, & -1 < x < 0 \\ -1, & x \le -1 \\\end{array}\right.</math> | |||
- <math>\left \lbrace\begin{array}{rl} 2x + 1, & x \ge -1/2 \\ -2x - 1, & x < -1/2 \\\end{array}\right.</math> | |||
- <math>\left \lbrace\begin{array}{rl} 1, & x \ge 0 \\ 2x + 1, & -1/2 < x < 0 \\ -2x - 1, & -1 \le x \le -1/2 \\ -1, & x \le -1 \\\end{array}\right.</math> | |||
{Suppose <math>a < b</math> are real numbers. For an real number <math>x</math>, define <math>f(x)</math> as the minimum of the distances from <math>x</math> to <math>a</math> and <math>b</math>. In other words, <math>\! f(x) := \min \{ |x - a|, |x - b| \}</math>. Which of the following is the correct piecewise linear definition of <math>f</math>? | |||
|type="()"} | |||
- <math>\left \lbrace\begin{array}{rl} a - x, & x \le a \\ x - (a + b)/2, & a <x < b \\ x - b, & x \ge b \\\end{array}\right.</math> | |||
- <math>\left \lbrace\begin{array}{rl} a - x, & x \le a \\ x - a, & a <x < b \\ x - b, & x \ge b \\\end{array}\right.</math> | |||
- <math>\left \lbrace\begin{array}{rl} a - x, & x \le a \\b - x, & a <x < b \\ x - b, & x \ge b \\\end{array}\right.</math> | |||
- <math>\left \lbrace\begin{array}{rl} a - x, & x \le a \\x - a, & a <x < (b - a)/2 \\ b - x, & (b - a)/2 \le x < b \\ x - b,& x \ge b \\\end{array}\right.</math> | |||
+ <math>\left \lbrace\begin{array}{rl} a - x, & x \le a \\x - a, & a <x < (b + a)/2 \\ b - x, & (b + a)/2 \le x < b \\ x - b, & x \ge b \\\end{array}\right.</math> | |||
{Suppose <math>a_1 < a_2 < \dots < a_n</math> are <math>n</math> distinct real numbers. For an real number <math>x</math>, define <math>f(x)</math> as the minimum of the distances from <math>x</math> to each of the numbers <math>a_1,a_2,\dots,a_n</math>. In other words, <math>\! f(x) := \min \{ |x - a_1|, |x - a_2|, |x - a_3|, \dots, |x - a_n| \}</math>. How many different linear pieces does the correct piecewise linear definition of <math>f</math> have? | |||
|type="()"} | |||
- <math>n</math> | |||
- <math>n + 1</math> | |||
- <math>2n - 2</math> | |||
- <math>2n - 1</math> | |||
+ <math>2n</math> | |||
|| The pieces will be <math>a_1 - x, x - a_1, a_2 - x,x - a_2, \dots, a_n - x, x - a_n</math>. There are <math>2n</math> pieces in total. | |||
</quiz> | |||
==Pointwise combination (computational)== | |||
<quiz display=simple> | <quiz display=simple> | ||
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- <math>\left \lbrace\begin{array}{rl} x^2 + x + 1, & x < 1 \\ x^2 + 2x + 3, & 1 \le x \le 2 \\ x^3 + 2x + 3, & x > 2 \\\end{array}\right.</math> | - <math>\left \lbrace\begin{array}{rl} x^2 + x + 1, & x < 1 \\ x^2 + 2x + 3, & 1 \le x \le 2 \\ x^3 + 2x + 3, & x > 2 \\\end{array}\right.</math> | ||
- <math>\left \lbrace\begin{array}{rl} x^2 + x + 1, & x < 2 \\ x^3 + 2x + 3, & 2 \le x \le 3 \\ x^2 + 2x + 3, & x > 3 \\\end{array}\right.</math> | - <math>\left \lbrace\begin{array}{rl} x^2 + x + 1, & x < 2 \\ x^3 + 2x + 3, & 2 \le x \le 3 \\ x^2 + 2x + 3, & x > 3 \\\end{array}\right.</math> | ||
</quiz> | </quiz> | ||
Latest revision as of 22:18, 19 October 2011
This quiz is related to piecewise definition of function.
Converting to and from piecewise definitions
Pointwise combination (computational)
Continuity and pointwise combination
Composition
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Differentiation
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