Limit is multiplicative: Difference between revisions

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==Statement==
==Statement==


Suppose <math>f</math> and <math>g</math> are [[function]]s of one variable. Suppose <math>c \in \R</math> is such that both <math>f</math> and <math>g</math> are defined on the immediate left and the immediate right of <math>c</math>. Further, suppose that the [[fact about::limit]]s <math>\lim_{x \to c} f(x)</math> and <math>\lim_{x \to c} g(x)</math> both exist (as finite numbers). In that case, the limit of the [[fact about::pointwise product of functions]] <math>f \cdot g</math> exists and is the product of the individual limits:
===Statement for two functions===
 
Suppose <math>f</math> and <math>g</math> are [[function]]s of one variable. Suppose <math>c \in \R</math> is such that both <math>f</math> and <math>g</math> are defined on the immediate left and the immediate right of <math>c</math>. Further, suppose that the [[fact about::limit]]s <math>\lim_{x \to c} f(x)</math> and <math>\lim_{x \to c} g(x)</math> both exist (as finite numbers). In that case, the limit of the [[fact about::pointwise product of functions]] <math>f \cdot g</math> exists at <math>c</math> and is the product of the individual limits:


<math>\lim_{x \to c} (f \cdot g)(x) = \lim_{x \to c} f(x) \cdot \lim_{x \to c} g(x)</math>
<math>\lim_{x \to c} (f \cdot g)(x) = \lim_{x \to c} f(x) \cdot \lim_{x \to c} g(x)</math>
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<math>\lim_{x \to c}[f(x)g(x)] = \lim_{x \to c} f(x) \cdot \lim_{x \to c}g(x)</math>
<math>\lim_{x \to c}[f(x)g(x)] = \lim_{x \to c} f(x) \cdot \lim_{x \to c}g(x)</math>
===Statement for multiple functions===
Suppose <math>f_1,f_2,\dots,f_n</math> are all functions defined on the immediate left and immediate right of a point <math>c \in \R</math>, and that all the limits <math>\lim_{x \to c} f_1(x)</math>, <math>\lim_{x \to c} f_2(x)</math>, <math>\dots</math>, <math>\lim_{x \to c} f_n(x)</math> exist (as finite numbers). Then, the limit of the pointwise product of functions <math>f_1 \cdot f_2 \cdot \dots \cdot f_n</math> exists at <math>c</math> and is the product of the individual limits:
<math>\lim_{x \to c} (f_1 \cdot f_2 \cdot \dots f_n)(x) = \lim_{x \to c} f_1(x) \lim_{x \to c} f_2(x) \dots \lim_{x \to c} f_n(x)</math>
===One-sided versions===
The statements above have valid one-sided versions. For the left versions, we need both the functions to be defined on the immediate left of <math>c</math>. For the right versions, we need the functions to be defined on the immediate right of <math>c</math>.
Each of the statements below is true whenever the right side expressions make sense:
* <math>\lim_{x \to c^-} [f(x)g(x)]] \lim_{x \to c^-} f(x) \cdot \lim_{x \to c^-} g(x)</math>
* <math>\lim_{x \to c^+} [f(x)g(x)]] \lim_{x \to c^+} f(x) \cdot \lim_{x \to c^+} g(x)</math>
* <math>\lim_{x \to c^-} (f_1 \cdot f_2 \cdot \dots f_n)(x) = \lim_{x \to c^-} f_1(x) \lim_{x \to c^-} f_2(x) \dots \lim_{x \to c^-} f_n(x)</math>
* <math>\lim_{x \to c^+} (f_1 \cdot f_2 \cdot \dots f_n)(x) = \lim_{x \to c^+} f_1(x) \lim_{x \to c^+} f_2(x) \dots \lim_{x \to c^+} f_n(x)</math>

Latest revision as of 01:52, 16 October 2011

Statement

Statement for two functions

Suppose and are functions of one variable. Suppose is such that both and are defined on the immediate left and the immediate right of . Further, suppose that the limits and both exist (as finite numbers). In that case, the limit of the pointwise product of functions exists at and is the product of the individual limits:

Equivalenty:

Statement for multiple functions

Suppose are all functions defined on the immediate left and immediate right of a point , and that all the limits , , , exist (as finite numbers). Then, the limit of the pointwise product of functions exists at and is the product of the individual limits:

One-sided versions

The statements above have valid one-sided versions. For the left versions, we need both the functions to be defined on the immediate left of . For the right versions, we need the functions to be defined on the immediate right of .

Each of the statements below is true whenever the right side expressions make sense: