Limit is linear

From Calculus

Statement

In terms of additivity and pulling out scalars

Additive:

Suppose f and g are functions of one variable. Suppose c∈R is such that both f and g are defined on the immediate left and the immediate right of c. Further, suppose that the limits limx→cf(x) and limx→cg(x) both exist (as finite numbers). In that case, the limit of the pointwise sum of functions f+g exists and is the sum of the individual limits:

limx→c(f+g)(x)=limx→cf(x)+limx→cg(x)

An equivalent formulation:

limx→c[f(x)+g(x)]=limx→cf(x)+limx→cg(x)

Scalars: Suppose f is a function of one variable and λ is a real number. Suppose c∈R is such that f is defined on the immediate left and immediate right of c, and that limx→cf(x) exists. Then:

limx→c(λf)(x)=λlimx→cf(x)

An equivalent formulation:

limx→cλf(x)=λlimx→cf(x)

In terms of generalized linearity

Suppose f1,f2,…,fn are functions and a1,a2,…,an are real numbers.

limx→c[a1f1(x)+a2f2(x)+…+anfn(x)]=a1limx→cf1(x)+a2limx→cf2(x)+…+anlimx→cfn(x)

if the right side expression makes sense.

In particular, setting n=2,a1=1,a2=−1, we get that the limit of the difference is the difference of the limits.

One-sided version

One-sided limits (i.e., the left hand limit and the right hand limit) are also linear. In other words, we have the following, whenever the respective right side expressions make sense:

  • limx→c−[f(x)+g(x)]=limx→c−f(x)+limx→c−g(x)
  • limx→c+[f(x)+g(x)]=limx→c+f(x)+limx→c+g(x)
  • limx→c−λf(x)=λlimx→c−f(x)
  • limx→c+λf(x)=λlimx→c+f(x)
  • limx→c−[a1f1(x)+a2f2(x)+…+anfn(x)]=a1limx→c−f1(x)+a2limx→c−f2(x)+…+anlimx→c−fn(x)
  • limx→c+[a1f1(x)+a2f2(x)+…+anfn(x)]=a1limx→c+f1(x)+a2limx→c+f2(x)+…+anlimx→c+fn(x)