Difference between revisions of "Product rule for partial differentiation"

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(Statement for directional derivatives)
(Statement for gradient vectors)
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| generic point, named functions || Suppose <math>f,g</math> are both real-valued functions of a vector variable <math>\overline{x}</math>. Then, we have the following product rule for [[gradient vector]]s wherever the right side expression makes sense:<br><math>\! \nabla_{\overline{u}}(fg)=  f(\overline{x})\nabla (g)(\overline{x}) + g(\overline{x}) \nabla (f)(\overline{x})</math>. Note that the products on the right side are scalar-vector multiplications.
 
| generic point, named functions || Suppose <math>f,g</math> are both real-valued functions of a vector variable <math>\overline{x}</math>. Then, we have the following product rule for [[gradient vector]]s wherever the right side expression makes sense:<br><math>\! \nabla_{\overline{u}}(fg)=  f(\overline{x})\nabla (g)(\overline{x}) + g(\overline{x}) \nabla (f)(\overline{x})</math>. Note that the products on the right side are scalar-vector multiplications.
 
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| generic point, named functions, point-free notation || Suppose <math>f,g</math> are both real-valued functions of a vector variable <math>\overline{x}</math>. Suppose <math>\overline{u}</math> is a unit vector. Suppose <math>\overline{x_0}</math> is a point in the domain of both functions. Then, we have the following product rule for [[gradient vector]]s wherever the right side expression makes sense:<br><math>\! \nabla(fg) =  f\nabla (g) + g\nabla (f)</math>. Note that the products on the right side are scalar-vector multiplications.
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| generic point, named functions, point-free notation || Suppose <math>f,g</math> are both real-valued functions of a vector variable <math>\overline{x}</math>. Then, we have the following product rule for [[gradient vector]]s wherever the right side expression makes sense:<br><math>\! \nabla(fg) =  f\nabla (g) + g\nabla (f)</math>. Note that the products on the right side are scalar-vector multiplications.
 
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Revision as of 04:19, 2 April 2012

Statement for two functions

Statement for partial derivatives

Version type Statement for functions of two variables
specific point, named functions Suppose f,g are both functions of variables x,y. Suppose (x_0,y_0) is a point in the domain of both f and g. Suppose the partial derivatives f_x(x_0,y_0) and g_x(x_0,y_0) both exist. Let fg denote the product of the functions. Then, we have:
(fg)_x(x_0,y_0) =f_x(x_0,y_0)g(x_0,y_0) + f(x_0,y_0)g_x(x_0,y_0)
Suppose the partial derivatives f_y(x_0,y_0) and g_y(x_0,y_0) both exist. Then, we have:
(fg)_y(x_0,y_0) = f_y(x_0,y_0)g(x_0,y_0) + f(x_0,y_0)g_y(x_0,y_0)
generic point, named functions Suppose f,g are both functions of variables x,y.
(fg)_x(x,y) =f_x(x,y)g(x,y) + f(x,y)g_x(x,y)
(fg)_y(x,y) = f_y(x,y)g(x,y) + f(x,y)g_y(x,y)
These hold wherever the right side expressions make sense.
generic point, named functions, point-free notation Suppose f,g are both functions of variables x,y.
(f g)_x =f_xg + fg_x
(f g)_y = f_yg + fg_y
These hold wherever the right side expressions make sense.

Statement for directional derivatives

Version type Statement
specific point, named functions Suppose f,g are both real-valued functions of a vector variable \overline{x}. Suppose \overline{u} is a unit vector. Suppose \overline{x_0} is a point in the domain of both functions. Then, we have the following product rule for directional derivatives:
\! \nabla_{\overline{u}}(fg)(\overline{x_0}) =  f(\overline{x_0})\nabla_{\overline{u}}(g)(\overline{x_0}) + g(\overline{x_0}) \nabla_{\overline{u}}(f)(\overline{x_0})
generic point, named functions Suppose f,g are both real-valued functions of a vector variable \overline{x}. Suppose \overline{u} is a unit vector. Then, we have the following product rule for directional derivatives wherever the right side expression makes sense:
\! \nabla_{\overline{u}}(fg)(\overline{x}) =  f(\overline{x})\nabla_{\overline{u}}(g)(\overline{x}) + g(\overline{x}) \nabla_{\overline{u}}(f)(\overline{x}).
generic point, named functions, point-free notation Suppose f,g are both real-valued functions of a vector variable \overline{x}. Suppose \overline{u} is a unit vector. Then, we have the following product rule for directional derivatives wherever the right side expression makes sense:
\! \nabla_{\overline{u}}(fg) =  f\nabla_{\overline{u}}(g) + g\nabla_{\overline{u}}(f).

The rule applies at all points where the right side make sense.

Statement for gradient vectors

Version type Statement
specific point, named functions Suppose f,g are both real-valued functions of a vector variable \overline{x}. Suppose \overline{x_0} is a point in the domain of both functions. Then, we have the following product rule for gradient vectors:
\! \nabla(fg)(\overline{x_0}) =  f(\overline{x_0})\nabla (g)(\overline{x_0}) + g(\overline{x_0}) \nabla (f)(\overline{x_0}). Note that the products on the right side are scalar-vector multiplications.
generic point, named functions Suppose f,g are both real-valued functions of a vector variable \overline{x}. Then, we have the following product rule for gradient vectors wherever the right side expression makes sense:
\! \nabla_{\overline{u}}(fg)=  f(\overline{x})\nabla (g)(\overline{x}) + g(\overline{x}) \nabla (f)(\overline{x}). Note that the products on the right side are scalar-vector multiplications.
generic point, named functions, point-free notation Suppose f,g are both real-valued functions of a vector variable \overline{x}. Then, we have the following product rule for gradient vectors wherever the right side expression makes sense:
\! \nabla(fg) =  f\nabla (g) + g\nabla (f). Note that the products on the right side are scalar-vector multiplications.

Statement for multiple functions

Statement for partial derivatives

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Statement for directional derivatives

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Statement for gradient vectors

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