Quadratic formula

Statement

Consider a quadratic equation of the form:

$ax^{2}+bx+c=0,a,b,c\in \mathbb {R} ,a\neq 0$

This is treated as an equation in $x$. The quadratic formula is a formula to determine the solutions of this equation. The short version of the formula is that the roots are:

${\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}$

if the expression makes sens; otherwise there are no roots.

To understand the formula, first define the discriminant of the quadratic function $ax^{2}+bx+c$ as the value $b^{2}-4ac$. Now, we make three cases:

Case for discriminant $b^{2}-4ac$	Conclusion for roots	Conclusion for factorization of polynomial $ax^{2}+bx+c$
positive, i.e., $b^{2}-4ac>0$	there are two real roots, given as ${\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}$ and $<math>{\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}$	If we denote the roots by $\alpha ,\beta$, then $ax^{2}+bx+c=a(x-\alpha )(x-\beta )$
zero, i.e., $b^{2}-4ac=0$	there is a single real root with multiplicity two, and that root is $-b/2a</mah>||<math>ax^{2}+bx+c=a(x+(b/2a))^{2}$
negative, i.e., $b^{2}-4ac<0$	there are no real roots	the polynomial does not factor, i.e., it is irreducible