Odd positive power of sine function: Difference between revisions

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(Created page with "==Definition== This page is about functions of the form: <math>x \mapsto (\sin x)^n</math> where <math>n</math> is an odd positive integer, i.e., <math>n = 2k + 1</math> for <...")
 
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| 1 || 3 || [[sine-cubed function]] || <math>\frac{\cos^3x}{3} - \cos x + C</math>
| 1 || 3 || [[sine-cubed function]] || <math>\frac{\cos^3x}{3} - \cos x + C</math>
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| 2 || 5 || [[fifth power of sine function]] || - \frac{\cos^5x}{5} + \frac{2\cos^3x}{3} - \cos x + C</math>
| 2 || 5 || [[fifth power of sine function]] || <math> - \frac{\cos^5x}{5} + \frac{2\cos^3x}{3} - \cos x + C</math>
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Revision as of 14:31, 4 September 2011

Definition

This page is about functions of the form:

x↦(sinx)n

where n is an odd positive integer, i.e., n=2k+1 for k a nonnegative integer.

Integration

First antiderivative: as a polynomial in cosine

We consider n=2k+1, k a nonnegative integer:

∫sin2k+1xdx

Rewrite sin2k+1x=sin2kxsinx=(1−cos2x)ksinx. We get:

∫(1−cos2x)k(sinx)dx

Set u=cosx, and we get:

∫−(1−u2)kdu

This is a polynomial integration in u. After obtaining the answer, we plug back u=cosx.

Here is the general integration in terms of binomial coefficients: [SHOW MORE]

We consider the integration in some small cases:

k n=2k+1 sinn Antiderivative as a polynomial in cos
0 1 sine function −cosx+C
1 3 sine-cubed function cos3x3−cosx+C
2 5 fifth power of sine function −cos5x5+2cos3x3−cosx+C