Integration of linear transform of function: Difference between revisions

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(Created page with "==Statement== Suppose <math>F</math> is an antiderivative for <math>f</math>. Then: <math>\int f(mx + \varphi) \, dx = \frac{1}{m}F(mx + \varphi)</math> where <math>m</mat...")
 
 
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Suppose <math>F</math> is an [[antiderivative]] for <math>f</math>. Then:
Suppose <math>F</math> is an [[antiderivative]] for <math>f</math>. Then:


<math>\int f(mx + \varphi) \, dx = \frac{1}{m}F(mx + \varphi)</math>
<math>\int f(mx + \varphi) \, dx = \frac{1}{m}F(mx + \varphi) + C</math>


where <math>m</math> is a nonzero real number and <math>\varphi</math> is a (possibly zero and possibly nonzero) real number).
where <math>m</math> is a nonzero real number and <math>\varphi</math> is a (possibly zero and possibly nonzero) real number). The "+ C" is the usual arbitrary constant addition.


This is a special case of [[integration by u-substitution]] where we put in <math>u = mx + \varphi</math>.
This is a special case of [[integration by u-substitution]] where we put in <math>u = mx + \varphi</math>.

Latest revision as of 02:01, 19 December 2011

Statement

Suppose F is an antiderivative for f. Then:

f(mx+φ)dx=1mF(mx+φ)+C

where m is a nonzero real number and φ is a (possibly zero and possibly nonzero) real number). The "+ C" is the usual arbitrary constant addition.

This is a special case of integration by u-substitution where we put in u=mx+φ.