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	<title>Repeated differentiation is linear - Revision history</title>
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	<updated>2026-04-10T18:47:06Z</updated>
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		<title>Vipul: Created page with &quot;{{differentiation rule}}  ==Statement==  For &lt;math&gt;k&lt;/math&gt; a positive integer, denote by &lt;math&gt;f^{(k)}&lt;/math&gt; the function obtained by differentiating &lt;math&gt;f&lt;/math&gt; a total of ...&quot;</title>
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		<updated>2011-09-05T14:03:08Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;{{differentiation rule}}  ==Statement==  For &amp;lt;math&amp;gt;k&amp;lt;/math&amp;gt; a positive integer, denote by &amp;lt;math&amp;gt;f^{(k)}&amp;lt;/math&amp;gt; the function obtained by differentiating &amp;lt;math&amp;gt;f&amp;lt;/math&amp;gt; a total of ...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;{{differentiation rule}}&lt;br /&gt;
&lt;br /&gt;
==Statement==&lt;br /&gt;
&lt;br /&gt;
For &amp;lt;math&amp;gt;k&amp;lt;/math&amp;gt; a positive integer, denote by &amp;lt;math&amp;gt;f^{(k)}&amp;lt;/math&amp;gt; the function obtained by differentiating &amp;lt;math&amp;gt;f&amp;lt;/math&amp;gt; a total of &amp;lt;math&amp;gt;k&amp;lt;/math&amp;gt; times. The operation &amp;lt;math&amp;gt;f \mapsto f^{(k)}&amp;lt;/math&amp;gt; is a linear operator. We give two equivalent ways of stating this below.&lt;br /&gt;
&lt;br /&gt;
===In terms of additivity and pulling out scalars===&lt;br /&gt;
&lt;br /&gt;
The following are true:&lt;br /&gt;
&lt;br /&gt;
* &amp;#039;&amp;#039;Repeated differentiation is additive&amp;#039;&amp;#039;, or &amp;#039;&amp;#039;&amp;lt;math&amp;gt;k^{th}&amp;lt;/math&amp;gt; derivative of sum is sum of derivatives&amp;#039;&amp;#039;: If &amp;lt;math&amp;gt;f&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;g&amp;lt;/math&amp;gt; are functions that are both differentiable at &amp;lt;math&amp;gt;x = x_0&amp;lt;/math&amp;gt;, we have:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{d^k}{dx^k}[f(x) + g(x)]_{x = x_0} = f^{(k)}(x_0) + g^{(k)}(x_0)&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
or equivalently:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;(f + g)^{(k)}(x_0) = f^{(k)}(x_0) + g^{(k)}(x_0)&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
In point-free notation:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;(f + g)^{(k)} = f^{(k)} + g^{(k)}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
* &amp;#039;&amp;#039;Constants (also called scalars) can be pulled out of differentiations&amp;#039;&amp;#039;: If &amp;lt;math&amp;gt;f&amp;lt;/math&amp;gt; is differentiable at &amp;lt;math&amp;gt;x = x_0&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;\lambda&amp;lt;/math&amp;gt; is a real number, then:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{d^k}{dx^k}[\lambda f(x)]|_{x = x_0} = \lambda f^{(k)}(x_0)&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===In terms of generalized linearity===&lt;br /&gt;
&lt;br /&gt;
Suppose &amp;lt;math&amp;gt;f_1, f_2, \dots, f_n&amp;lt;/math&amp;gt; are functions that are all differentiable at a point &amp;lt;math&amp;gt;x_0&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;a_1, a_2, \dots, a_n&amp;lt;/math&amp;gt; are real numbers. Then:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{d^k}{dx^k}[a_1f_1(x) + a_2f_2(x) + \dots + a_nf_n(x)]|_{x = x_0} = a_1f_1^{(k)}(x_0) + a_2f_2^{(k)}(x_0) + \dots + a_nf_n^{(k)}(x_0)&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
==Related rules==&lt;br /&gt;
&lt;br /&gt;
* [[Differentiation is linear]]&lt;br /&gt;
* [[Product rule for differentiation]]&lt;br /&gt;
* [[Product rule for higher derivatives]]&lt;br /&gt;
* [[Chain rule for differentiation]]&lt;br /&gt;
* [[Chain rule for higher derivatives]]&lt;br /&gt;
* [[Quotient rule for differentiation]]&lt;/div&gt;</summary>
		<author><name>Vipul</name></author>
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